관리-도구
편집 파일: IterPermute.py
from functools import reduce def iterpermute(*args): args = [iter(a) for a in args] la = len(args) stopped = [0] * la lens = [0] * la bufs = [[] for i in range(la)] nexts = [None] * la n = 0 while 1: anynew = 0 for i in range(la): if stopped[i]: nextval = bufs[i][n % lens[i]] else: try: nextval = next(args[i]) except StopIteration: if lens[i] == 0: # raise ValueError, 'The iterator passed in arg %d did not return any item'%i return stopped[i] = 1 nextval = bufs[i][n % lens[i]] else: anynew = 1 bufs[i].append(nextval) lens[i] += 1 nexts[i] = nextval if anynew: n += 1 yield tuple(nexts) else: break wanted = reduce(lambda x, y: x*y, lens, 1) if n >= wanted: assert n == wanted return ixs = list(enumerate(lens)) ixs.sort(key=lambda x: x[1]) ixs = [ix for (ix, ln) in ixs] jxs = [0] * la seen = dict([(tuple([j % lens[i] for i in ixs]), 1) for j in range(n)]) while n < wanted: t = tuple([jxs[i] for i in ixs]) if t not in seen: yield tuple([bufs[i][jxs[i]] for i in range(la)]) n += 1 for i in ixs: j = jxs[i] j = (j + 1) % lens[i] jxs[i] = j if j != 0: break def test_iterpermute(): import itertools repeat = itertools.repeat assert list(iterpermute()) == [()] assert list(iterpermute(repeat(1, 2))) == [(1,), (1,)] assert list(iterpermute(repeat(1, 1), repeat(2, 1))) == [(1, 2)] assert list(iterpermute(list(range(0, 2)), list(range(2, 3)))) == [ (0, 2), (1, 2)] assert list(iterpermute(list(range(0, 2)), list(range(2, 4)))) == [ (0, 2), (1, 3), (1, 2), (0, 3)] print(list(iterpermute(list(range(0, 2)), list(range(0, 3))))) print(list(iterpermute(list(range(0, 3)), list(range(0, 2))))) if __name__ == '__main__': test_iterpermute()